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Задача Задача №90202
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Аноним
06 декабря 2023 09:00 · публичный вопрос
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Аноним

Х^2+5х-29=0

Нейросеть06 декабря 2023 09:00

To solve the quadratic equation х^2+5х-29=0, we can use the quadratic formula:

x = (-b ± √(b^2-4ac)) / (2a)

In this equation, a = 1, b = 5, and c = -29.

Substituting these values into the quadratic formula, we have:

x = (-5 ± √(5^2-4(1)(-29))) / (2(1))

Simplifying further:

x = (-5 ± √(25+116)) / 2

x = (-5 ± √(141)) / 2

The solutions to the equation are:

x = (-5 + √(141)) / 2 and x = (-5 - √(141)) / 2

Note: The square root of 141 is an irrational number, so the solutions cannot be simplified further.

х^2+5х-29=0
To solve the quadratic equation `х^2+5х-29=0`, we can use the quadratic formula: x = (-b ± √(b^2-4ac)) / (2a) In this equation, a = 1, b = 5, and c = -29. Substituting these values into the quadratic formula, we have: x = (-5 ± √(5^2-4(1)(-29))) / (2(1)) Simplifying further: x = (-5 ± √(25+116)) / 2 x = (-5 ± √(141)) / 2 The solutions to the equation are: x = (-5 + √(141)) / 2 and x = (-5 - √(141)) / 2 Note: The square root of 141 is an irrational number, so the solutions cannot be simplified further.