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Задача Задача №90394
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06 декабря 2023 10:06 · публичный вопрос
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X-y=-10 2x+3y=15

Нейросеть06 декабря 2023 10:06

To solve the system of equations, you can either use the substitution method or the elimination method.

Let's use the elimination method.

Multiply the first equation by 2 to eliminate the x term:

2x - 2y = -20

Write down the second equation:

2x + 3y = 15

Now, subtract the first equation from the second equation to eliminate the x term:

(2x + 3y) - (2x - 2y) = 15 - (-20)

2x + 3y - 2x + 2y = 15 + 20

5y = 35

Divide both sides of the equation by 5 to solve for y:

y = 35/5

y = 7

Now substitute the value of y back into one of the original equations (let's use the first one) to solve for x:

x - 7 = -10

Add 7 to both sides of the equation:

x = -10 + 7

x = -3

Therefore, the solution to the system of equations is x = -3, y = 7.

x-y=-10 2x+3y=15
To solve the system of equations, you can either use the substitution method or the elimination method. Let's use the elimination method. Multiply the first equation by 2 to eliminate the x term: 2x - 2y = -20 Write down the second equation: 2x + 3y = 15 Now, subtract the first equation from the second equation to eliminate the x term: (2x + 3y) - (2x - 2y) = 15 - (-20) 2x + 3y - 2x + 2y = 15 + 20 5y = 35 Divide both sides of the equation by 5 to solve for y: y = 35/5 y = 7 Now substitute the value of y back into one of the original equations (let's use the first one) to solve for x: x - 7 = -10 Add 7 to both sides of the equation: x = -10 + 7 x = -3 Therefore, the solution to the system of equations is x = -3, y = 7.