X-y=-10 2x+3y=15

To solve this system of equations, we can use either the substitution method or the elimination method.

Let's solve it using the elimination method:

Multiply the first equation by 2 to make the coefficients of x in both equations the same:

2(x - y) = 2(-10) 2x - 2y = -20

Now we have the system of equations:

2x - 2y = -20 2x + 3y = 15

Next, subtract the first equation from the second equation:

(2x + 3y) - (2x - 2y) = 15 - (-20) 2x + 3y - 2x + 2y = 15 + 20 5y = 35

Divide both sides by 5:

5y/5 = 35/5 y = 7

Now, substitute the value of y back into one of the original equations. Let's use the first equation:

x - 7 = -10 x = -10 + 7 x = -3

So the solution to the system of equations is x = -3 and y = 7.