M=9 v0=500м/с m1=5кг m2= 4кг V1 = +200м/с = 700м/с V2-?

To find V2, we can use the principle of conservation of momentum. The total momentum before the collision is equal to the total momentum after the collision.

Total momentum before collision = Total momentum after collision

(m1 * V1) + (m2 * V2) = (m1 * v1) + (m2 * v2)

Now, let's plug in the values we have:

(5 kg * 200 m/s) + (4 kg * V2) = (5 kg * 500 m/s) + (4 kg * v2)

1000 kgm/s + 4 kgV2 = 2500 kgm/s + 4 kgv2

Subtracting 4 kg*v2 from both sides:

1000 kgm/s + 4 kgV2 - 4 kgv2 = 2500 kgm/s

1000 kgm/s + 4 kg(V2 - v2) = 2500 kg*m/s

Dividing both sides by 4 kg:

250 kgm/s + V2 - v2 = 625 kgm/s

Subtracting 250 kg*m/s from both sides:

V2 - v2 = 375 kg*m/s

Finally, adding v2 to both sides to isolate V2:

V2 = 375 kg*m/s + v2

Since the initial velocity of the second object (v2) is not given, we cannot determine the value of V2 without more information.