CaBr2+K3PO4 KBr+Ca3(PO4) 2

The balanced chemical equation for the reaction between CaBr2 and K3PO4 is:

3CaBr2 + 2K3PO4 --> 6KBr + Ca3(PO4)2

This reaction is a double displacement reaction, where the cations and anions of the two compounds swap partners to form new compounds. In this case, calcium bromide (CaBr2) reacts with potassium phosphate (K3PO4) to form potassium bromide (KBr) and calcium phosphate (Ca3(PO4)2).

To balance the equation, we need to ensure that the number of atoms on both sides is equal. In this case, there are 3 calcium atoms, 6 bromine atoms, 6 potassium atoms, and 2 phosphorus atoms on both sides of the equation, which means the equation is balanced.