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Задача Задача №98787
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Аноним
08 декабря 2023 14:38 · публичный вопрос
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Аноним

132(х+5) /(х-5) (х+5) -132(х-5) /(х-5) (х+5) =5(х-5) (х+5) /(х-5) (х+5)

Нейросеть08 декабря 2023 14:38

To simplify the equation, let's start by canceling out the common factors in the numerators and denominators:

132(x+5)/(x-5)(x+5) - 132(x-5)/(x-5)(x+5) = 5(x-5)(x+5)/(x-5)(x+5)

Canceling out the common factors gives us:

132/(x-5) - 132/(x+5) = 5

Now, let's find a common denominator:

The common denominator is (x-5)(x+5).

Multiplying the numerator and denominator of the first fraction by (x+5), and the numerator and denominator of the second fraction by (x-5), we get:

132(x+5)(x+5) - 132(x-5)(x-5) = 5(x-5)(x+5)

Expanding and simplifying the equation further:

132(x^2 + 10x + 25) - 132(x^2 - 10x + 25) = 5(x^2 - 25)

132x^2 + 1320x + 3300 - 132x^2 + 1320x - 3300 = 5x^2 - 125

Combining like terms:

2640x = 5x^2 - 125

Bringing all the terms to one side:

5x^2 - 2640x - 125 = 0

Now we have a quadratic equation.

To solve for x, you can use the quadratic formula:

x = (-b ± √(b^2 - 4ac))/(2a)

In this case, a = 5, b = -2640, and c = -125.

Plugging these values into the quadratic formula, you can find the solutions for x.

132(х+5) /(х-5) (х+5) -132(х-5) /(х-5) (х+5) =5(х-5) (х+5) /(х-5) (х+5)
To simplify the equation, let's start by canceling out the common factors in the numerators and denominators: 132(x+5)/(x-5)(x+5) - 132(x-5)/(x-5)(x+5) = 5(x-5)(x+5)/(x-5)(x+5) Canceling out the common factors gives us: 132/(x-5) - 132/(x+5) = 5 Now, let's find a common denominator: The common denominator is (x-5)(x+5). Multiplying the numerator and denominator of the first fraction by (x+5), and the numerator and denominator of the second fraction by (x-5), we get: 132(x+5)(x+5) - 132(x-5)(x-5) = 5(x-5)(x+5) Expanding and simplifying the equation further: 132(x^2 + 10x + 25) - 132(x^2 - 10x + 25) = 5(x^2 - 25) 132x^2 + 1320x + 3300 - 132x^2 + 1320x - 3300 = 5x^2 - 125 Combining like terms: 2640x = 5x^2 - 125 Bringing all the terms to one side: 5x^2 - 2640x - 125 = 0 Now we have a quadratic equation. To solve for x, you can use the quadratic formula: x = (-b ± √(b^2 - 4ac))/(2a) In this case, a = 5, b = -2640, and c = -125. Plugging these values into the quadratic formula, you can find the solutions for x.