(3; - 1) x + z = 4+y x + (y - 3) - 5 = 0

To solve this system of equations, let's rearrange them:

First equation: x + z = 4 + y Second equation: x + (y - 3) - 5 = 0

We can simplify the second equation:

x + y - 3 - 5 = 0 x + y - 8 = 0

Now let's solve the system of equations:

1. x + z = 4 + y
2. x + y - 8 = 0

To do this, we can substitute equation (2) into equation (1):

(x + y - 8) + z = 4 + y x + y + z - 8 = 4 + y

Now we can simplify this equation:

x + z - 8 = 4

Rearrange to solve for z:

z = 4 - x + 8 z = 12 - x

Now we have a new system of equations:

1. x + z = 4 + y
2. z = 12 - x

We can further substitute equation (2) into equation (1):

x + (12 - x) = 4 + y

Now simplify this equation:

12 = 4 + y

Subtract 4 from both sides:

12 - 4 = y 8 = y

So the value of y is 8.

Now substitute y = 8 back into equation (2):

z = 12 - x

Substitute y = 8 and solve for z:

z = 12 - x z = 12 - 3 z = 9

So the value of z is 9.

Finally, we can substitute y = 8 and z = 9 back into equation (1):

x + z = 4 + y x + 9 = 4 + 8 x + 9 = 12 x = 12 - 9 x = 3

So the value of x is 3.

Therefore, the solution to the system of equations is x = 3, y = 8, and z = 9.