Х+2у=0 х+у-2х+7у=8

To solve the system of equations, we can use the method of substitution or elimination. Let's use the method of substitution.

From the first equation, we have: x + 2y = 0 -> x = -2y

Now, substitute this value of x into the second equation:

x + y - 2x + 7y = 8 -2y + y - 2(-2y) + 7y = 8 -y + 4y + 7y = 8 12y = 8 y = 8/12 y = 2/3

Now that we have the value of y, we can substitute it back into the first equation to find x:

x + 2(2/3) = 0 x + 4/3 = 0 x = -4/3

Therefore, the solution to the system of equations is x = -4/3 and y = 2/3.