Х+2у=0 х+у-2х+7у=8

To solve the system of equations, we can use the method of substitution or elimination.

Let's solve it using the method of substitution.

From the first equation, we have: x + 2y = 0 ---> (Equation 1)

We can rearrange this equation to solve for x: x = -2y ---> (Equation 2)

Now, substitute Equation 2 into the second equation: x + y - 2x + 7y = 8

Replace x with -2y: -2y + y - 2(-2y) + 7y = 8

Simplify the equation: -y + y + 4y + 7y = 8 12y = 8 y = 8/12 y = 2/3

Now substitute the value of y back into Equation 2 to find x: x = -2y x = -2(2/3) x = -4/3

Therefore, the solution to the system of equations is x = -4/3 and y = 2/3.