(-3-2y)³

To expand the expression \((-3 - 2y)^3\), we can use the binomial theorem or directly apply the formula for the cube of a binomial: \[ (a+b)^3 = a^3 + 3a^2b + 3ab^2 + b^3 \] In this case, let \(a = -3\) and \(b = -2y\). Now, we can calculate each term: 1. \(a^3 = (-3)^3 = -27\) 2. \(3a^2b = 3(-3)^2(-2y) = 3(9)(-2y) = -54y\) 3. \(3ab^2 = 3(-3)(-2y)^2 = 3(-3)(4y^2) = -36y^2\) 4. \(b^3 = (-2y)^3 = -8y^3\) Now, combining all these terms together: \[ (-3 - 2y)^3 = -27 - 54y - 36y^2 - 8y^3 \] Thus, the expanded form is: \[ -8y^3 - 36y^2 - 54y - 27 \]