Log½(4-x)

To simplify the expression \(\log_{\frac{1}{2}}(4 - x)\), you can utilize the change of base formula or properties of logarithms. Here’s how you can work with it: 1. **Change of Base Formula**: The change of base formula states that \(\log_b(a) = \frac{\log_k(a)}{\log_k(b)}\) for any base \(k\). Here, we can use base 10 or base \(e\) (natural logarithm): \[ \log_{\frac{1}{2}}(4 - x) = \frac{\log(4 - x)}{\log\left(\frac{1}{2}\right)} \] 2. **Evaluating \(\log\left(\frac{1}{2}\right)\)**: Since \(\frac{1}{2} = 2^{-1}\), we get: \[ \log\left(\frac{1}{2}\right) = \log(2^{-1}) = -\log(2) \] Thus, the logarithm can be rewritten as: \[ \log_{\frac{1}{2}}(4 - x) = -\frac{\log(4 - x)}{\log(2)} \] 3. **Final Result**: Therefore, the simplified form of \(\log_{\frac{1}{2}}(4 - x)\) is: \[ -\frac{\log(4 - x)}{\log(2)} \] This processed any logarithmic properties that could be beneficial for calculations or further exploration of values depending on \(x\). If you have specific requirements or limits for \(x\), such as \(x < 4\), to ensure the logarithm is defined, please let me know!