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Задача Задача №2627847
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14 января 2025 07:50 · публичный вопрос
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Аноним

cos =0,8 3π/2<a<2π Найти sin a, the a, ctg a

Ответ нейросети
14 января 2025 07:50

Given that \(\cos a = 0.8\) and the angle \(a\) is in the interval \(\frac{3\pi}{2} < a < 2\pi\), we can find the sine and cotangent values.

  1. Identify the quadrant:

    • The interval \(\frac{3\pi}{2} < a < 2\pi\) indicates that angle \(a\) is in the fourth quadrant, where sine is negative and cosine is positive.
  2. Use the Pythagorean identity: \[ \sin^2 a + \cos^2 a = 1 \] Substituting the known value of \(\cos a\): \[ \sin^2 a + (0.8)^2 = 1 \\ \sin^2 a + 0.64 = 1 \\ \sin^2 a = 1 - 0.64 \\ \sin^2 a = 0.36 \\ \sin a = -\sqrt{0.36} = -0.6 \] (We take the negative root since \(a\) is in the fourth quadrant!)

  3. Calculate cotangent: \[ \cot a = \frac{\cos a}{\sin a} \] Substituting the values of \(\cos a\) and \(\sin a\): \[ \cot a = \frac{0.8}{-0.6} = -\frac{4}{3} \]

To summarize:

  • \(\sin a = -0.6\)
  • \(\cot a = -\frac{4}{3}\)

Thus, the values are:

  • \(\sin a = -0.6\)
  • \(a\) in radians can be calculated as \(a \approx 5.36\) (you can calculate the exact angle in radians using inverse cosine, but within the fourth quadrant and in the specified interval).
  • \(\cot a = -\frac{4}{3}\)