3х-6≤7х+2

To solve the inequality \(3x - 6 \leq 7x + 2\), follow these steps: 1. **Move all terms involving \(x\) to one side** and constant terms to the other side. Subtract \(7x\) from both sides: \[ 3x - 7x - 6 \leq 2 \] This simplifies to: \[ -4x - 6 \leq 2 \] 2. **Add 6 to both sides** to isolate the term with \(x\): \[ -4x \leq 2 + 6 \] Simplifying that gives: \[ -4x \leq 8 \] 3. **Divide both sides by -4**. Remember that when you divide by a negative number, you must flip the inequality sign: \[ x \geq \frac{8}{-4} \] This simplifies to: \[ x \geq -2 \] The solution to the inequality is: \[ x \geq -2 \] This means that \(x\) can be any number greater than or equal to \(-2\).