3х-6≤7х+2

To solve the inequality \(3x - 6 \leq 7x + 2\), follow these steps:

1. Move all terms involving \(x\) to one side and constant terms to the other side. Subtract \(7x\) from both sides:

   \[ 3x - 7x - 6 \leq 2 \]

   This simplifies to:

   \[ -4x - 6 \leq 2 \]

2. Add 6 to both sides to isolate the term with \(x\):

   \[ -4x \leq 2 + 6 \]

   Simplifying that gives:

   \[ -4x \leq 8 \]

3. Divide both sides by -4. Remember that when you divide by a negative number, you must flip the inequality sign:

   \[ x \geq \frac{8}{-4} \]

   This simplifies to:

   \[ x \geq -2 \]

The solution to the inequality is:

\[ x \geq -2 \]

This means that \(x\) can be any number greater than or equal to \(-2\).