8х²+bx+2=0

To solve the quadratic equation \(8x^2 + bx + 2 = 0\), we need to know more about the parameter \(b\) or the specific question related to this equation.

For example, if you want to find the roots of the equation, we can apply the quadratic formula:

\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]

In this case, \(a = 8\), \(b = b\), and \(c = 2\). So, the quadratic formula becomes:

\[ x = \frac{-b \pm \sqrt{b^2 - 4 \cdot 8 \cdot 2}}{2 \cdot 8} \]

This simplifies to:

\[ x = \frac{-b \pm \sqrt{b^2 - 64}}{16} \]

If you have a specific scenario or value of \(b\) you want to explore, or if you need to determine conditions such as the nature of the roots (real and distinct, real and equal, or complex), please provide that information!