7•x+51=100 41-36÷x=29

Let's solve each equation step by step.

Equation 1: \( 7x + 51 = 100 \)

1. Subtract 51 from both sides: \[ 7x + 51 - 51 = 100 - 51 \] \[ 7x = 49 \]

2. Divide both sides by 7: \[ x = \frac{49}{7} \] \[ x = 7 \]

Equation 2: \( 41 - \frac{36}{x} = 29 \)

1. Subtract 41 from both sides: \[ 41 - \frac{36}{x} - 41 = 29 - 41 \] \[ -\frac{36}{x} = -12 \]

2. Multiply both sides by -1: \[ \frac{36}{x} = 12 \]

3. Multiply both sides by \( x \): \[ 36 = 12x \]

4. Divide both sides by 12: \[ x = \frac{36}{12} \] \[ x = 3 \]

Summary of Solutions:

• For the equation \( 7x + 51 = 100 \), \( x = 7 \).
• For the equation \( 41 - \frac{36}{x} = 29 \), \( x = 3 \).