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Вопрос от Анонимного юзера 22 января 2025 12:12

5-x / x+4 >0

Ответ нейросети

22 января 2025 12:12

To solve the inequality ( \frac{5 - x}{x + 4} > 0 ), we need to find the values of ( x ) for which the fraction is positive.

Step 1: Determine when the numerator and denominator are positive or negative.

Numerator: ( 5 - x )

  • ( 5 - x > 0 ) when ( x < 5 ) (since we want the numerator to be positive).

Denominator: ( x + 4 )

  • ( x + 4 > 0 ) when ( x > -4 ) (since we want the denominator to be positive).

Step 2: Analyze the signs of the expression

Next, we will determine the sign of ( \frac{5 - x}{x + 4} ) in the intervals formed by the critical points ( x = -4 ) and ( x = 5 ).

Critical Points:

  1. ( x = -4 ) (denominator changes sign)
  2. ( x = 5 ) (numerator changes sign)

The intervals to examine are:

  • ( (-\infty, -4) )
  • ( (-4, 5) )
  • ( (5, \infty) )

Step 3: Test each interval

  1. Interval: ( (-\infty, -4) )

    • Choose ( x = -5 ): [ \frac{5 - (-5)}{-5 + 4} = \frac{10}{-1} = -10 \quad (\text{Negative}) ]
  2. Interval: ( (-4, 5) )

    • Choose ( x = 0 ): [ \frac{5 - 0}{0 + 4} = \frac{5}{4} \quad (\text{Positive}) ]
  3. Interval: ( (5, \infty) )

    • Choose ( x = 6 ): [ \frac{5 - 6}{6 + 4} = \frac{-1}{10} \quad (\text{Negative}) ]

Step 4: Compile the results

From this analysis, we find:

  • The inequality ( \frac{5 - x}{x + 4} > 0 ) holds true in the interval ( (-4, 5) ).

Step 5: Check endpoints

  • At ( x = -4 ): The denominator becomes zero (undefined).
  • At ( x = 5 ): The numerator becomes zero (equals zero, not greater than zero).

Final Solution

Thus, the solution for the inequality ( \frac{5 - x}{x + 4} > 0 ) is:

[ \boxed{(-4, 5)} ]

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5-x / x+4 >0
To solve the inequality \( \frac{5 - x}{x + 4} > 0 \), we need to find the values of \( x \) for which the fraction is positive. ### Step 1: Determine when the numerator and denominator are positive or negative. **Numerator**: \( 5 - x \) - \( 5 - x > 0 \) when \( x < 5 \) (since we want the numerator to be positive). **Denominator**: \( x + 4 \) - \( x + 4 > 0 \) when \( x > -4 \) (since we want the denominator to be positive). ### Step 2: Analyze the signs of the expression Next, we will determine the sign of \( \frac{5 - x}{x + 4} \) in the intervals formed by the critical points \( x = -4 \) and \( x = 5 \). **Critical Points**: 1. \( x = -4 \) (denominator changes sign) 2. \( x = 5 \) (numerator changes sign) The intervals to examine are: - \( (-\infty, -4) \) - \( (-4, 5) \) - \( (5, \infty) \) ### Step 3: Test each interval 1. **Interval**: \( (-\infty, -4) \) - Choose \( x = -5 \): \[ \frac{5 - (-5)}{-5 + 4} = \frac{10}{-1} = -10 \quad (\text{Negative}) \] 2. **Interval**: \( (-4, 5) \) - Choose \( x = 0 \): \[ \frac{5 - 0}{0 + 4} = \frac{5}{4} \quad (\text{Positive}) \] 3. **Interval**: \( (5, \infty) \) - Choose \( x = 6 \): \[ \frac{5 - 6}{6 + 4} = \frac{-1}{10} \quad (\text{Negative}) \] ### Step 4: Compile the results From this analysis, we find: - The inequality \( \frac{5 - x}{x + 4} > 0 \) holds true in the interval \( (-4, 5) \). ### Step 5: Check endpoints - At \( x = -4 \): The denominator becomes zero (undefined). - At \( x = 5 \): The numerator becomes zero (equals zero, not greater than zero). ### Final Solution Thus, the solution for the inequality \( \frac{5 - x}{x + 4} > 0 \) is: \[ \boxed{(-4, 5)} \]