4а-xa+5b+yb=0

To solve the equation \( 4a - xa + 5b + yb = 0 \), we can rearrange it in terms of \( a \) and \( b \). Let's isolate \( a \) and \( b \): Rearranging the equation: \[ 4a - xa + 5b + yb = 0 \] This can be rewritten as: \[ (4 - x)a + (5 + y)b = 0 \] For this equation to hold, either: 1. The coefficients of \( a \) and \( b \) must both be zero, or 2. The terms can be balanced where one coefficient can be expressed in terms of the other. Setting both coefficients to zero gives us: 1. \( 4 - x = 0 \) ➔ \( x = 4 \) 2. \( 5 + y = 0 \) ➔ \( y = -5 \) Thus, the values of \( x \) and \( y \) that make this equation true are: - \( x = 4 \) - \( y = -5 \) If you need to express \( a \) and \( b \) in terms of each other or require other types of solutions, please specify!