(6, 4 -5, 75) * (-1\2) +5 3\4 * -1\2=?

To solve the expression \((6, 4 - 5, 75) * (-1/2) + 5 3/4 * (-1/2)\), we first need to clarify the notation used. It looks like we are working with fractions and mixed numbers.

Let’s break the problem down step-by-step.

1. Convert Mixed Numbers to Improper Fractions:

   • For the first mixed number \(6\) and \(4 - 5\):
     • If we assume \(4 - 5\) to mean \(4\frac{5}{75}\), then it appears to be a slightly miswritten mixed number. To proceed, we’ll treat \(4\) as is and convert \(5.75\) to perform calculations later.
     • If we consider \(4 - 5\) as a negative operation on \(4\) then we would have to clarify, but for calculation, this seems off.
   • For \(5\) and \(3/4\):
     • \(5 \frac{3}{4} = \frac{5 \times 4 + 3}{4} = \frac{20 + 3}{4} = \frac{23}{4}\)

2. Calculating Each Part:

   • For \( (6, 4 - 5, 75) \) we will interpret entirely as a augmented form proper addition or another function as needed.
   • For the negative half:
     • We represent \((-1/2)\) as-is.

   Now the breakdown: \[ (6 \times (-1/2)) + (5 \frac{3}{4} \times (-1/2)) \]

   • Calculating \(6 \times (-1/2) = -3\).
   • Calculating \(\frac{23}{4} \times (-1/2)\):
     • \(\frac{23}{4} \times \frac{-1}{2} = \frac{-23}{8}\)

3. Combining Results:

   • We need to combine \(-3\) and \(-\frac{23}{8}\).
   • Convert \(-3\) to eighths:
     • \(-3 = \frac{-24}{8}\)
   • Now add them: \[ \frac{-24}{8} + \frac{-23}{8} = \frac{-24 - 23}{8} = \frac{-47}{8} \]

Thus the final result for \( (6 \frac{4}{75}) \times (-1/2) + 5 \frac{3}{4} \times (-1/2) = \frac{-47}{8} \) or as a mixed number:

\[ -\frac{47}{8} = -5 \frac{7}{8} \]

So the answer to the expression is:

\[ \boxed{-5 \frac{7}{8}} \]