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13 февраля 2025 05:39
To solve the chain of transformations, we're dealing with the chemical properties of aluminum compounds and some general chemistry reactions.
Chain of Transformations
( \text{Al(OH)}_3 \xrightarrow{t} \text{Al}_2\text{O}_3 + \text{H}_2\text{O} )
- Explanation: When aluminum hydroxide ( \text{Al(OH)}_3 ) is heated, it decomposes to form aluminum oxide ( \text{Al}_2\text{O}_3 ) and water. This is a typical dehydration reaction of hydroxides.
( \text{Al}_2\text{O}_3 + 2 \text{NaOH} \xrightarrow{\text{fusion}} 2 \text{NaAlO}_2 + \text{H}_2\text{O} )
- Explanation: Aluminum oxide reacts with sodium hydroxide when melted together to form sodium aluminate ( \text{NaAlO}_2 ) and water. This is an example of aluminum oxide acting as an acid (acidic oxide) in a reaction with a base.
( \text{NaAlO}_2 + 4 \text{HCl} \rightarrow \text{AlCl}_3 + \text{NaCl} + 2 \text{H}_2\text{O} )
- Explanation: Sodium aluminate reacts with hydrochloric acid to form aluminum chloride ( \text{AlCl}_3 ), sodium chloride ( \text{NaCl} ), and water. Here, the aluminate ion is neutralized by the acid.
( \text{AlCl}_3 + 3 \text{LiOH} \rightarrow \text{Al(OH)}_3 + 3 \text{LiCl} )
- Explanation: Aluminum chloride reacts with lithium hydroxide, leading to the formation of aluminum hydroxide and lithium chloride. This is a double displacement reaction where the (\text{Cl}^-) and (\text{OH}^-) ions trade partners.
Summary of Process
- Dehydration: (\text{Al(OH)}_3) is heated to form (\text{Al}_2\text{O}_3).
- Fusion with Base: (\text{Al}_2\text{O}_3) reacts with (\text{NaOH}) to produce (\text{NaAlO}_2).
- Acid Neutralization: (\text{NaAlO}_2) is treated with (\text{HCl}) to yield (\text{AlCl}_3).
- Regeneration of Hydroxide: (\text{AlCl}_3) reacts with (\text{LiOH}) to form (\text{Al(OH)}_3).
This series of reactions demonstrates the characteristics of aluminum compounds as both an acid and a base (amphoteric behavior), as well as the typical interaction of metal hydroxides, oxides, and halides with acids and bases.
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