To simplify the expressions you've provided, we'll apply the difference of squares formula and distributive property where applicable. Here are the steps for each one:
(2a-3b)(2a+3b)
This follows the formula \( (x-y)(x+y) = x^2 - y^2 \).
\[ = (2a)^2 - (3b)^2 = 4a^2 - 9b^2 \]
(10x-6c)(10x+6c)
Using the difference of squares:
\[ = (10x)^2 - (6c)^2 = 100x^2 - 36c^2 \]
(5a^2 - 2x^3)(2x^3 + 5a)
This requires distributing:
\[ = 5a^2(2x^3) + 5a(5a^2) - 2x^3(2x^3) - 2x^3(5a) \] \[ = 10a^2x^3 + 25a^3 - 4x^6 - 10ax^3 \]
(2 + 53112 - 13)
This expression seems to be arithmetic rather than a product; simplifying yields:
\[ = 2 + 53112 - 13 = 53101 \]
(5a^3 - 6x^3)(6x^3 + 5a^3)
Again, using the difference of squares:
\[ = (5a^3)^2 - (6x^3)^2 = 25a^6 - 36x^6 \]
(5x^2 + 2y^3)(5x^2 - 2y^3)
This also uses the difference of squares:
\[ = (5x^2)^2 - (2y^3)^2 = 25x^4 - 4y^6 \]
(a^3 - b^3)(a^3 + b^3)
This follows the difference of squares:
\[ = (a^3)^2 - (b^3)^2 = a^6 - b^6 \]
(0.7x + y^3)(0.7x - y^3)
Using the difference of squares:
\[ = (0.7x)^2 - (y^3)^2 = 0.49x^2 - y^6 \]
(0.4c + 0.8y^3)(0.8y^2 - 0.4c)
Distributing here:
\[ = 0.4c(0.8y^2) - 0.4c(0.4c) + 0.8y^3(0.8y^2) - 0.8y^3(0.4c) \] \[ = 0.32cy^2 - 0.16c^2 + 0.64y^5 - 0.32cy^3 \]
(0.4x^3 - 0.7y^3)(0.7y^3 + 0.4x^3)
Again using the difference of squares:
\[ = (0.4x^3)^2 - (0.7y^3)^2 = 0.16x^6 - 0.49y^6 \]
These simplifications cover all provided expressions. If you have any more expressions to simplify or any questions about these solutions, feel free to ask!