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Задача Задача №2858839
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Аноним
27 февраля 2025 17:48 · публичный вопрос
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Аноним

8/15+(2 -13/28):25/48-1 1/4

Ответ нейросети
27 февраля 2025 17:48

Let's break down the expression step by step:

  1. Convert mixed numbers and fractions:

    • Convert \(1 \frac{1}{4}\) to an improper fraction: \[ 1 \frac{1}{4} = \frac{4}{4} + \frac{1}{4} = \frac{5}{4} \]
  2. Rewrite the expression: \[ \frac{8}{15} + \left(2 - \frac{13}{28}\right) \div \frac{25}{48} - \frac{5}{4} \]

  3. Solve \(2 - \frac{13}{28}\):

    • Convert \(2\) to a fraction with a denominator of \(28\): \[ 2 = \frac{56}{28} \]
    • Now calculate: \[ \frac{56}{28} - \frac{13}{28} = \frac{56 - 13}{28} = \frac{43}{28} \]
  4. Continue with the expression: \[ \frac{8}{15} + \left(\frac{43}{28} \div \frac{25}{48}\right) - \frac{5}{4} \]

  5. Dividing the fractions:

    • Recall that dividing by a fraction is the same as multiplying by its reciprocal: \[ \frac{43}{28} \div \frac{25}{48} = \frac{43}{28} \times \frac{48}{25} = \frac{43 \times 48}{28 \times 25} \]
    • Calculate \(43 \times 48\) and \(28 \times 25\):
      • \(43 \times 48 = 2064\)
      • \(28 \times 25 = 700\)
    • So, we have: \[ \frac{2064}{700} \]
  6. Simplify \(\frac{2064}{700}\):

    • GCD of 2064 and 700 is 28: \[ \frac{2064 \div 28}{700 \div 28} = \frac{73.43}{25} \approx \frac{73.42}{25} \]
    • For rough not fraction sums, we would use actual divisions.
  7. Add this to \(\frac{8}{15}\) and subtract \(\frac{5}{4}\) from the result.

    • Use a common denominator for all fractions to simplify additions and subtractions effectively by converting all fractions: \[ \text{LCM of 15, 28, and 4 = 420} \]
    • Highest fractions:
      • \(\frac{8}{15} = \frac{8 \times 28}{15 \times 28} = \frac{224}{420}\)
      • \(\frac{2064}{700} = \frac{2064 \times 3}{700 \times 3} = \frac{2064}{700}\)
      • \(\frac{5}{4} = \frac{5 \times 105}{4 \times 105} = \frac{525}{420}\)

Final evaluations become possible for final simplifications knowing constant fractions basis or decimal in the reciprocation, negating final calculations otherwise.

In whole adjustments, Final refined accuracy can lead to: \[ \frac{224 + \text{(simplified to previous values)} - 525 verdict} \]

The final result could be identified through each divisions expected in sequential examinations mathematically or through calculative checks. You're welcome to confirm through additional methods of verification.