U=90B g=3,6нКл d=0,3*10^-3м с-?е-?

To find the speed of the electrons (с) and the electric field strength (е) from the given information, we will use the following relationships: 1. The electric field \( e \) can be calculated using the formula for the potential difference (U) and the distance (d) between the plates: \[ e = \frac{U}{d} \] 2. The speed of the electrons (с) can be found using the formula derived from energy considerations, specifically the kinetic energy (K.E.) gained by the electron, which equals the work done on it by the electric field: \[ K.E. = e \cdot U \] The kinetic energy can also be expressed as: \[ K.E. = \frac{1}{2} m v^2 \] Where \( m \) is the mass of the electron (\( m \approx 9.11 \times 10^{-31} \) kg). Now, let's calculate both: 1. First calculate the electric field (e): - Given: - \( U = 90B \) (the value of \( B \) isn't provided, so we'll express the result in terms of \( B \)) - \( d = 0.3 \times 10^{-3} \) m - Using the formula: \[ e = \frac{U}{d} = \frac{90B}{0.3 \times 10^{-3}} \] Let's calculate this: \[ e = \frac{90B}{0.3 \times 10^{-3}} = \frac{90B}{0.0003} = 300000B \, \text{V/m} \] 2. Next, let's calculate the speed of the electrons (с): - The electric charge of the electron \( g = 3.6 \, \text{нКл} = 3.6 \times 10^{-9} \, \text{C} \). - The total electric potential energy will give the electrons kinetic energy when they accelerate. - Setting the energies equal: \[ e \cdot U = \frac{1}{2} m c^2 \] Rearranging gives: \[ c = \sqrt{\frac{2eU}{m}} \] Substituting \( U = 90B \): \[ c = \sqrt{\frac{2(3.6 \times 10^{-9})(90B)}{9.11 \times 10^{-31}}} \] Performing the calculation: \[ c = \sqrt{\frac{2 \cdot 3.6 \cdot 90 \cdot B \times 10^{-9}}{9.11 \times 10^{-31}}} \] You would need to substitute \( B \) to solve numerically. The final expressions for both the electric field strength \( e \) and the speed of electrons \( c \) will depend on the value of \( B \) you choose to substitute. Please provide the value of \( B \) to continue with numerical calculations.