To solve the equation \( \frac{5}{x-7} = \frac{7}{x-5} \), we first need to find a common denominator to simplify the equation:
\( \frac{5}{x-7} = \frac{7}{x-5} \)
To find the common denominator, multiply the denominators together:
\( (x-7)(x-5) = x^2 -7x -5x +35 = x^2 -12x +35 \)
Now rewrite the equation with the common denominator:
\( \frac{5}{x-7} = \frac{7}{x-5} \)
\( \frac{5(x-5)}{(x-7)(x-5)} = \frac{7(x-7)}{(x-7)(x-5)} \)
\( \frac{5x-25}{x^2 -12x +35} = \frac{7x-49}{x^2 -12x +35} \)
Now we can cancel out the denominators:
\( 5x - 25 = 7x - 49 \)
Now, solve for x:
\( 5x - 25 = 7x - 49 \)
Subtract 5x from both sides:
\( -25 = 2x - 49 \)
Add 49 to both sides:
\( 24 = 2x \)
Divide by 2:
\( x = 12 \)
Therefore, the solution to the equation \( \frac{5}{x-7} = \frac{7}{x-5} \) is \( x = 12 \).