To solve this system of linear equations, we can use the method of substitution or elimination. Let's use the elimination method to solve these two equations:
Given equations:
- 3x - 2y = -4
- 5x - 3y = -6
To eliminate y, we can multiply the first equation by 3 and the second equation by 2:
- 9x - 6y = -12
- 10x - 6y = -12
Now, subtract the second equation from the first equation to eliminate y:
(9x - 6y) - (10x - 6y) = -12 - (-12) 9x - 6y - 10x + 6y = -12 + 12 -x = 0 x = 0
Now substitute x = 0 into one of the original equations, let's use equation 1:
3(0) - 2y = -4 -2y = -4 y = 2
Therefore, the solution to the system of equations is x = 0 and y = 2.