K2Cr2О7, + KI+ HSO4 = Cr2(SO4)3 + I2 + K2S04 + H20

Let's analyze and balance the chemical equation:

Unbalanced equation: \[ \text{K}_2\text{Cr}_2\text{O}_7 + \text{KI} + \text{HSO}_4^- \rightarrow \text{Cr}_2(\text{SO}_4)_3 + \text{I}_2 + \text{K}_2\text{SO}_4 + \text{H}_2\text{O} \]

Step 1: Assign oxidation states

• K₂Cr₂O₇: K is +1, O is -2, Cr is +6
• KI: I is -1
• HSO₄⁻: H +1, S +6, O -2
• Cr₂(SO₄)₃: Cr +3, S +6
• I₂: I is 0
• K₂SO₄: K +1, S +6, O -2
• H₂O: H +1, O -2

Step 2: Identify what's oxidized and reduced

• Iodide (I⁻) in KI is oxidized to I₂ (0)
• Chromium (Cr⁶+ in dichromate) is reduced to Cr³+ in Cr₂(SO₄)₃

Step 3: Write half-reactions

Oxidation: \[ 2 I^- \rightarrow I_2 + 2 e^- \] Reduction: \[ \text{Cr}_2\text{O}_7^{2-} + 14 H^+ + 6 e^- \rightarrow 2 Cr^{3+} + 7 H_2O \]

(Note: In basic or neutral medium, H⁺ can be balanced with H₂O or OH⁻)

Since HSO₄⁻ is present, the medium is slightly acidic, so we'd balance accordingly.

Step 4: Balance the overall reaction

Assuming acidic medium:

• The chromate reduction:
  \[ \text{Cr}_2\text{O}_7^{2-} + 14 H^+ + 6 e^- \rightarrow 2 Cr^{3+} + 7 H_2O \]

• Iodide oxidation:
  \[ 2 I^- \rightarrow I_2 + 2 e^- \]

Multiply the oxidation half-reaction by 3 to balance electrons with reduction:
\[ 6 I^- \rightarrow 3 I_2 + 6 e^- \]

Now, combine:
\[ \text{Cr}_2\text{O}_7^{2-} + 14 H^+ + 6 e^- + 6 I^- \rightarrow 2 Cr^{3+} + 7 H_2O + 3 I_2 \]

Step 5: Incorporate the reactants and products

• Recognize that K₂Cr₂O₇ provides Cr₂O₇²⁻
• K and other ions are spectator ions balancing charge and atoms

Given the initial reactants and final products, the balanced overall reaction in acidic solution is:

\[ K_2Cr_2O_7 + 6 KI + 8 H_2SO_4 \rightarrow 2 Cr_2(SO_4)_3 + 6 I_2 + K_2SO_4 + 4 H_2O \]

Final balanced equation:

\[ \boxed{ K_2Cr_2O_7 + 6 KI + 8 H_2SO_4 \rightarrow 2 Cr_2(SO_4)_3 + 6 I_2 + K_2SO_4 + 4 H_2O } \]

Summary:

• 1 molecule of potassium dichromate reacts with 6 molecules of potassium iodide.
• 8 molecules of sulfuric acid provide the acidic medium.
• Products are chromium sulfate, iodine, potassium sulfate, and water.

Let me know if you'd like a detailed step-by-step explanation or help with a different problem!