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Вопрос от Анонимного юзера 25 сентября 2025 17:55

F(x)=x2cosx

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25 сентября 2025 17:55

Assuming you mean f(x) = x^2 cos x, here are handy facts and formulas for exam prep.

  • Domain and basic properties

    • Domain: all real numbers.
    • f is even: f(-x) = f(x).
  • First derivative (useful for increasing/decreasing and critical points)

    • f'(x) = 2x cos x − x^2 sin x
    • Critical points satisfy f'(x) = 0:
      • x = 0, or
      • 2x cos x − x^2 sin x = 0 ⇒ x(2 cos x − x sin x) = 0 ⇒ tan x = 2/x (for x ≠ 0)
    • There are infinitely many critical points, solutions of tan x = 2/x.
  • Second derivative (concavity and inflection)

    • f''(x) = derivative of (2x cos x − x^2 sin x)
    • f''(x) = (2 − x^2) cos x − 4x sin x
    • Inflection points satisfy f''(x) = 0 (no closed-form solution; numerical).
  • Maclaurin series (useful for small-x behavior)

    • cos x = 1 − x^2/2 + x^4/24 − …
    • f(x) = x^2 cos x = x^2 − (1/2)x^4 + (1/24)x^6 − …
    • In particular, near 0, f(x) ~ x^2 (positive for small x ≠ 0), with f(0) = 0.
  • Local behavior at 0

    • f(0) = 0, f''(0) = 2 > 0, so x = 0 is a local minimum (and the function is nonnegative near 0).
  • Antiderivative (indefinite integral)

    • ∫ x^2 cos x dx = x^2 sin x + 2x cos x − 2 sin x + C
  • Large-scale behavior

    • As |x| → ∞, f(x) = x^2 cos x oscillates with amplitude growing like x^2 (no horizontal asymptote).

If you want, tell me the exact task you’re studying (e.g., find increasing/decreasing intervals, locate inflection points numerically, compute a Taylor polynomial to a certain degree, or solve a specific problem), and I’ll tailor the steps and, if needed, provide approximate roots or plots.

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f(x)=x2cosx
Assuming you mean f(x) = x^2 cos x, here are handy facts and formulas for exam prep. - Domain and basic properties - Domain: all real numbers. - f is even: f(-x) = f(x). - First derivative (useful for increasing/decreasing and critical points) - f'(x) = 2x cos x − x^2 sin x - Critical points satisfy f'(x) = 0: - x = 0, or - 2x cos x − x^2 sin x = 0 ⇒ x(2 cos x − x sin x) = 0 ⇒ tan x = 2/x (for x ≠ 0) - There are infinitely many critical points, solutions of tan x = 2/x. - Second derivative (concavity and inflection) - f''(x) = derivative of (2x cos x − x^2 sin x) - f''(x) = (2 − x^2) cos x − 4x sin x - Inflection points satisfy f''(x) = 0 (no closed-form solution; numerical). - Maclaurin series (useful for small-x behavior) - cos x = 1 − x^2/2 + x^4/24 − … - f(x) = x^2 cos x = x^2 − (1/2)x^4 + (1/24)x^6 − … - In particular, near 0, f(x) ~ x^2 (positive for small x ≠ 0), with f(0) = 0. - Local behavior at 0 - f(0) = 0, f''(0) = 2 > 0, so x = 0 is a local minimum (and the function is nonnegative near 0). - Antiderivative (indefinite integral) - ∫ x^2 cos x dx = x^2 sin x + 2x cos x − 2 sin x + C - Large-scale behavior - As |x| → ∞, f(x) = x^2 cos x oscillates with amplitude growing like x^2 (no horizontal asymptote). If you want, tell me the exact task you’re studying (e.g., find increasing/decreasing intervals, locate inflection points numerically, compute a Taylor polynomial to a certain degree, or solve a specific problem), and I’ll tailor the steps and, if needed, provide approximate roots or plots.