To solve the expression \( \frac{2}{3} + \frac{1}{6} - \frac{1}{4} \), we first need to find a common denominator for the fractions.
The denominators are 3, 6, and 4. The least common multiple (LCM) of these numbers is 12.
Now we'll convert each fraction to have a denominator of 12:
- \( \frac{2}{3} = \frac{2 \times 4}{3 \times 4} = \frac{8}{12} \)
- \( \frac{1}{6} = \frac{1 \times 2}{6 \times 2} = \frac{2}{12} \)
- \( \frac{1}{4} = \frac{1 \times 3}{4 \times 3} = \frac{3}{12} \)
Now we can substitute these back into the expression:
\[ \frac{8}{12} + \frac{2}{12} - \frac{3}{12} \]
Adding and subtracting the fractions, we have:
\[ \frac{8 + 2 - 3}{12} = \frac{7}{12} \]
Thus, the final answer is:
\[ \frac{7}{12} \]