a1=17 d=3 a18=?

To find the 18th term (a18) of an arithmetic sequence, you can use the formula for the nth term of an arithmetic sequence:

\[ a_n = a_1 + (n - 1) \times d \]

Where:

• \(a_n\) is the nth term
• \(a_1\) is the first term
• \(d\) is the common difference
• \(n\) is the term number

Given:

• \(a_1 = 17\)
• \(d = 3\)
• \(n = 18\)

Plugging the values into the formula:

\[ a_{18} = 17 + (18 - 1) \times 3 \] \[ a_{18} = 17 + 17 \times 3 \] \[ a_{18} = 17 + 51 \] \[ a_{18} = 68 \]

Therefore, \(a_{18} = 68\).