A1=17 d=3 a18=?

To find the 18th term (a18) of an arithmetic sequence, you can use the formula for the nth term of an arithmetic sequence: \[ a_n = a_1 + (n - 1) \times d \] Where: - \(a_n\) is the nth term - \(a_1\) is the first term - \(d\) is the common difference - \(n\) is the term number Given: - \(a_1 = 17\) - \(d = 3\) - \(n = 18\) Plugging the values into the formula: \[ a_{18} = 17 + (18 - 1) \times 3 \] \[ a_{18} = 17 + 17 \times 3 \] \[ a_{18} = 17 + 51 \] \[ a_{18} = 68 \] Therefore, \(a_{18} = 68\).