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Вопрос от Алина ㅤ 18 января 2025 09:10

Y=-1/2|x|

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18 января 2025 09:10

The equation ( y = -\frac{1}{2}|x| ) represents a V-shaped graph that opens downwards due to the negative coefficient in front of the absolute value. Here are some key points regarding this equation:

Characteristics:

  1. Vertex: The vertex of the graph is at the origin ((0, 0)) since there are no horizontal or vertical shifts.

  2. Slope:

    • For ( x \geq 0 ), ( |x| = x ) so the equation becomes ( y = -\frac{1}{2}x ). This indicates that the slope of the line is (-\frac{1}{2}) in the first quadrant.
    • For ( x < 0 ), ( |x| = -x ) so the equation becomes ( y = \frac{1}{2}x ). This indicates that the slope of the line is ( \frac{1}{2}) in the second quadrant.
  3. Y-Intercept: The y-intercept occurs when ( x = 0 ). Here, ( y = 0 ), so the point is ((0, 0)).

  4. X-Intercepts: The only x-intercept occurs at ( y=0 ). Setting ( y = 0 ) gives ( |x| = 0 ), which means ( x = 0).

  5. Symmetry: The graph is symmetric about the y-axis because it contains the absolute value function which is even.

Graph:

To sketch the graph:

  • Start by plotting the vertex at the origin (0, 0).
  • From the vertex, draw lines with slopes of (-\frac{1}{2}) to the right and (\frac{1}{2}) to the left.
  • Extend the lines indefinitely to show that they continue in both directions.

Summary:

The graph of ( y = -\frac{1}{2}|x| ) is a V-shape, opening downwards with its vertex at the origin and symmetric about the y-axis. The lines have slopes of (-\frac{1}{2}) and (\frac{1}{2}) for ( x \geq 0) and ( x < 0) respectively.

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y=-1/2|x|
The equation \( y = -\frac{1}{2}|x| \) represents a V-shaped graph that opens downwards due to the negative coefficient in front of the absolute value. Here are some key points regarding this equation: ### Characteristics: 1. **Vertex**: The vertex of the graph is at the origin \((0, 0)\) since there are no horizontal or vertical shifts. 2. **Slope**: - For \( x \geq 0 \), \( |x| = x \) so the equation becomes \( y = -\frac{1}{2}x \). This indicates that the slope of the line is \(-\frac{1}{2}\) in the first quadrant. - For \( x < 0 \), \( |x| = -x \) so the equation becomes \( y = \frac{1}{2}x \). This indicates that the slope of the line is \( \frac{1}{2}\) in the second quadrant. 3. **Y-Intercept**: The y-intercept occurs when \( x = 0 \). Here, \( y = 0 \), so the point is \((0, 0)\). 4. **X-Intercepts**: The only x-intercept occurs at \( y=0 \). Setting \( y = 0 \) gives \( |x| = 0 \), which means \( x = 0\). 5. **Symmetry**: The graph is symmetric about the y-axis because it contains the absolute value function which is even. ### Graph: To sketch the graph: - Start by plotting the vertex at the origin (0, 0). - From the vertex, draw lines with slopes of \(-\frac{1}{2}\) to the right and \(\frac{1}{2}\) to the left. - Extend the lines indefinitely to show that they continue in both directions. ### Summary: The graph of \( y = -\frac{1}{2}|x| \) is a V-shape, opening downwards with its vertex at the origin and symmetric about the y-axis. The lines have slopes of \(-\frac{1}{2}\) and \(\frac{1}{2}\) for \( x \geq 0\) and \( x < 0\) respectively.