Y=-1/2|x|
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18 января 2025 09:10
The equation ( y = -\frac{1}{2}|x| ) represents a V-shaped graph that opens downwards due to the negative coefficient in front of the absolute value. Here are some key points regarding this equation:
Characteristics:
Vertex: The vertex of the graph is at the origin ((0, 0)) since there are no horizontal or vertical shifts.
Slope:
- For ( x \geq 0 ), ( |x| = x ) so the equation becomes ( y = -\frac{1}{2}x ). This indicates that the slope of the line is (-\frac{1}{2}) in the first quadrant.
- For ( x < 0 ), ( |x| = -x ) so the equation becomes ( y = \frac{1}{2}x ). This indicates that the slope of the line is ( \frac{1}{2}) in the second quadrant.
Y-Intercept: The y-intercept occurs when ( x = 0 ). Here, ( y = 0 ), so the point is ((0, 0)).
X-Intercepts: The only x-intercept occurs at ( y=0 ). Setting ( y = 0 ) gives ( |x| = 0 ), which means ( x = 0).
Symmetry: The graph is symmetric about the y-axis because it contains the absolute value function which is even.
Graph:
To sketch the graph:
- Start by plotting the vertex at the origin (0, 0).
- From the vertex, draw lines with slopes of (-\frac{1}{2}) to the right and (\frac{1}{2}) to the left.
- Extend the lines indefinitely to show that they continue in both directions.
Summary:
The graph of ( y = -\frac{1}{2}|x| ) is a V-shape, opening downwards with its vertex at the origin and symmetric about the y-axis. The lines have slopes of (-\frac{1}{2}) and (\frac{1}{2}) for ( x \geq 0) and ( x < 0) respectively.
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