To solve the quadratic equation \( x^2 - 2x - 35 = 0 \), we can either factor the equation or use the quadratic formula. Let's start with factoring.
We need to find two numbers that multiply to \(-35\) (the constant term) and add up to \(-2\) (the coefficient of \(x\)). The numbers \(-7\) and \(5\) satisfy these conditions since:
\[ -7 \times 5 = -35 \quad \text{and} \quad -7 + 5 = -2. \]
Thus, we can factor the quadratic equation as:
\[ (x - 7)(x + 5) = 0. \]
Setting each factor to zero gives us the solutions:
- \( x - 7 = 0 \) \(\Rightarrow\) \( x = 7 \)
- \( x + 5 = 0 \) \(\Rightarrow\) \( x = -5 \)
Therefore, the solutions to the equation \( x^2 - 2x - 35 = 0 \) are:
\[ x = 7 \quad \text{and} \quad x = -5. \]