2y2-1=0

To solve the equation \(2y^2 - 1 = 0\), follow these steps: 1. **Add 1 to both sides**: \[ 2y^2 = 1 \] 2. **Divide both sides by 2**: \[ y^2 = \frac{1}{2} \] 3. **Take the square root of both sides**: \[ y = \pm \sqrt{\frac{1}{2}} = \pm \frac{\sqrt{2}}{2} \] Therefore, the solutions to the equation \(2y^2 - 1 = 0\) are: \[ y = \frac{\sqrt{2}}{2} \quad \text{and} \quad y = -\frac{\sqrt{2}}{2} \]