N:=513 M:=2×(N diu 10) N:=N+M×2 N:=N mod 100

To solve for the final value of \( N \) given the operations, let's break down each step: 1. **Initialization:** \( N := 513 \) 2. **Calculate \( M \):** - First, we find \( N \text{ diu } 10 \). The operation "diu" refers to the integer division, which is equivalent to finding the quotient when dividing by 10. Thus, \[ N \text{ diu } 10 = 513 \div 10 = 51 \] - Now, we calculate \( M \): \[ M := 2 \times (N \text{ diu } 10) = 2 \times 51 = 102 \] 3. **Update \( N \):** \[ N := N + M \times 2 = 513 + 102 \times 2 \] - First, calculate \( M \times 2 \): \[ M \times 2 = 102 \times 2 = 204 \] - Now update \( N \): \[ N := 513 + 204 = 717 \] 4. **Final calculation for \( N \):** Now we compute \( N \mod 100 \): \[ N := 717 \mod 100 = 17 \] Therefore, the final result for \( N \) is \( \boxed{17} \).