N:=513 M:=2×(N diu 10) N:=N+M×2 N:=N mod 100

To solve for the final value of \( N \) given the operations, let's break down each step:

1. Initialization: \( N := 513 \)

2. Calculate \( M \):

   • First, we find \( N \text{ diu } 10 \). The operation "diu" refers to the integer division, which is equivalent to finding the quotient when dividing by 10. Thus, \[ N \text{ diu } 10 = 513 \div 10 = 51 \]
   • Now, we calculate \( M \): \[ M := 2 \times (N \text{ diu } 10) = 2 \times 51 = 102 \]

3. Update \( N \): \[ N := N + M \times 2 = 513 + 102 \times 2 \]

   • First, calculate \( M \times 2 \): \[ M \times 2 = 102 \times 2 = 204 \]
   • Now update \( N \): \[ N := 513 + 204 = 717 \]

4. Final calculation for \( N \): Now we compute \( N \mod 100 \): \[ N := 717 \mod 100 = 17 \]

Therefore, the final result for \( N \) is \( \boxed{17} \).