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Вопрос от Анонимного юзера 27 февраля 2025 10:53

1) (a + 7)(a - 7); 2) (6 + x)(x - 6); 3) (4b - 1)(4b + 1); 4) (8m + 3y) (3y - 8m); 5) (x - q°)(x" + q°); 6(Tay-love)7y 7y+|02); 7) (0,3p3 + 0,2q*)(0,3p8 - 0,2q*); 8) (x1 - y*)(x* + y*) (x8 + y8); 9) (m° - n°)(-m® - n°); 10) (1.3c)+⅔6 (⅔8-1.30x)

Ответ нейросети

27 февраля 2025 10:53

Let's go through each expression step by step to simplify them.

  1. (a + 7)(a - 7)
    This is a difference of squares.
    ((a + 7)(a - 7) = a^2 - 49)

  2. (6 + x)(x - 6)
    This can be rewritten as:
    ((6 + x)(x - 6) = x^2 - 36)

  3. (4b - 1)(4b + 1)
    This is also a difference of squares:
    ((4b - 1)(4b + 1) = (4b)^2 - 1^2 = 16b^2 - 1)

  4. (8m + 3y)(3y - 8m)
    Using the distributive property (FOIL):
    [ (8m + 3y)(3y - 8m) = 24my - 64m^2 + 9y^2 - 24my = -64m^2 + 9y^2 ]

  5. (x - q°)(x" + q°)
    Assuming (q°) and (x") are analogous to variables:
    This expression simplifies using the distributive property:
    [ (x - q)(x + q) = x^2 - (q^2) ]

  6. (7y + 0)^7y + 10
    It seems the formatting might be unclear, but simplifying gives:
    [ (7y + 0)(7y) + 10 = 49y^2 + 10 ]

  7. (0.3p^3 + 0.2q)(0.3p^8 - 0.2q)
    This is a difference of squares:
    [ (0.3p^3)^2 - (0.2q)^2 = 0.09p^6 - 0.04q^2 ]

  8. (x^1 - y^2)(x^2 + y^2)(x^8 + y^8)
    Assuming (y^2) in terms of both (x) and (y):
    This doesn't simplify easily without specific factorizations.

  9. (m^2 - n^2)(-m^2 - n^2)
    Rewriting it yields ( (a-b)(-c) = -abc ):
    [ (m^2 - n^2)(-m^2 - n^2) = -((m^2)^2 - (n^2)^2) = - (m^4 - n^4) ]

  10. (1.3c) + (⅔6)(⅔8 - 1.30x)
    This expression needs clarification but follows the distributive property:
    Using numerical values in computations yields:
    [ 1.3c + \frac{12}{3}( \frac{16 - 1.3x}{3}) = 1.3c + 4(16 - 1.30x) = 1.3c + 64 - 5.2x ]

This completes the simplifications. If you have any specific adjustments or another inquiry, let me know!

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1) (a + 7)(a - 7); 2) (6 + x)(x - 6); 3) (4b - 1)(4b + 1); 4) (8m + 3y) (3y - 8m); 5) (x - q°)(x" + q°); 6(Tay-love)7y 7y+|02); 7) (0,3p3 + 0,2q*)(0,3p8 - 0,2q*); 8) (x1 - y*)(x* + y*) (x8 + y8); 9) (m° - n°)(-m® - n°); 10) (1.3c)+⅔6 (⅔8-1.30x)
Let's go through each expression step by step to simplify them. 1) **(a + 7)(a - 7)** This is a difference of squares. \((a + 7)(a - 7) = a^2 - 49\) 2) **(6 + x)(x - 6)** This can be rewritten as: \((6 + x)(x - 6) = x^2 - 36\) 3) **(4b - 1)(4b + 1)** This is also a difference of squares: \((4b - 1)(4b + 1) = (4b)^2 - 1^2 = 16b^2 - 1\) 4) **(8m + 3y)(3y - 8m)** Using the distributive property (FOIL): \[ (8m + 3y)(3y - 8m) = 24my - 64m^2 + 9y^2 - 24my = -64m^2 + 9y^2 \] 5) **(x - q°)(x" + q°)** Assuming \(q°\) and \(x"\) are analogous to variables: This expression simplifies using the distributive property: \[ (x - q)(x + q) = x^2 - (q^2) \] 6) **(7y + 0)^7y + 10** It seems the formatting might be unclear, but simplifying gives: \[ (7y + 0)(7y) + 10 = 49y^2 + 10 \] 7) **(0.3p^3 + 0.2q)(0.3p^8 - 0.2q)** This is a difference of squares: \[ (0.3p^3)^2 - (0.2q)^2 = 0.09p^6 - 0.04q^2 \] 8) **(x^1 - y^2)(x^2 + y^2)(x^8 + y^8)** Assuming \(y^2\) in terms of both \(x\) and \(y\): This doesn't simplify easily without specific factorizations. 9) **(m^2 - n^2)(-m^2 - n^2)** Rewriting it yields \( (a-b)(-c) = -abc \): \[ (m^2 - n^2)(-m^2 - n^2) = -((m^2)^2 - (n^2)^2) = - (m^4 - n^4) \] 10) **(1.3c) + (⅔6)(⅔8 - 1.30x)** This expression needs clarification but follows the distributive property: Using numerical values in computations yields: \[ 1.3c + \frac{12}{3}( \frac{16 - 1.3x}{3}) = 1.3c + 4(16 - 1.30x) = 1.3c + 64 - 5.2x \] This completes the simplifications. If you have any specific adjustments or another inquiry, let me know!