To solve the expression \(-2 \frac{1}{3} \cdot \left(-\frac{9}{7}\right)\), we first need to convert the mixed number \(-2 \frac{1}{3}\) into an improper fraction.
Convert \(-2 \frac{1}{3}\) to an improper fraction: \[ -2 \frac{1}{3} = -\left(2 \cdot 3 + 1\right) / 3 = -\frac{6 + 1}{3} = -\frac{7}{3} \]
Now we multiply \(-\frac{7}{3}\) by \(-\frac{9}{7}\): \[ -\frac{7}{3} \cdot -\frac{9}{7} = \frac{7 \cdot 9}{3 \cdot 7} \]
The \(7\) in the numerator and denominator cancels out: \[ = \frac{9}{3} \]
Finally, simplify \(\frac{9}{3}\): \[ = 3 \]
Thus, the result of the expression \(-2 \frac{1}{3} \cdot (-\frac{9}{7})\) is \(3\).