6h12min+(3h45min-2h7min)

To solve the expression \(6 \text{h } 12 \text{min} + (3 \text{h } 45 \text{min} - 2 \text{h } 7 \text{min})\), we first need to solve the part inside the parentheses:

1. Calculate \(3 \text{h } 45 \text{min} - 2 \text{h } 7 \text{min}\):

   • Convert both times to minutes for easier subtraction:
     • \(3 \text{h } 45 \text{min} = 3 \times 60 + 45 = 180 + 45 = 225 \text{ min}\)
     • \(2 \text{h } 7 \text{min} = 2 \times 60 + 7 = 120 + 7 = 127 \text{ min}\)
   • Now, subtract the two:
     • \(225 \text{ min} - 127 \text{ min} = 98 \text{ min}\)

2. Convert \(98 \text{ min}\) back to hours and minutes:

   • \(98 \text{ min} = 1 \text{ h } 38 \text{ min}\) (since 98 divided by 60 gives us 1 hour and a remainder of 38 minutes).

3. Now, add this result to \(6 \text{h } 12 \text{min}\):

   • Convert \(6 \text{h } 12 \text{min}\) to minutes:
     • \(6 \times 60 + 12 = 360 + 12 = 372 \text{ min}\)
   • Add the minutes:
     • \(372 \text{ min} + 98 \text{ min} = 470 \text{ min}\)

4. Convert \(470 \text{ min}\) back to hours and minutes:

   • \(470 \text{ min} = 7 \text{ h } 50 \text{ min}\) (since 470 divided by 60 gives us 7 hours and a remainder of 50 minutes).

Thus, \(6 \text{h } 12 \text{min} + (3 \text{h } 45 \text{min} - 2 \text{h } 7 \text{min}) = 7 \text{h } 50 \text{min}\).