6х^2+9х-14=5х^2+9х+11

To solve the equation \(6x^2 + 9x - 14 = 5x^2 + 9x + 11\), first, bring all the terms to one side of the equation:

\(6x^2 + 9x - 14 - 5x^2 - 9x - 11 = 0\)

Combine like terms:

\(6x^2 - 5x^2 + 9x - 9x - 14 - 11 = 0\)

\(x^2 + 0x - 25 = 0\)

Now, you have a quadratic equation in the standard form \(ax^2 + bx + c = 0\), where \(a = 1\), \(b = 0\), and \(c = -25\).

To solve this quadratic equation, you can use the quadratic formula:

\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]

Plug in the values for \(a\), \(b\), and \(c\):

\[ x = \frac{-(0) \pm \sqrt{(0)^2 - 4(1)(-25)}}{2(1)} \]

\[ x = \pm \sqrt{100}/2 \]

\[ x = \pm 10/2 \]

Therefore, the solutions are:

\[ x = 5 \ \text{or} \ x = -5 \]