(1/3)^-3

To evaluate \(\left(\frac{1}{3}\right)^{-3}\): Using the property of exponents, \(a^{-n} = \frac{1}{a^n}\), \[ \left(\frac{1}{3}\right)^{-3} = \left(\frac{1}{3}\right)^{-1 \times 3} = \left(\left(\frac{1}{3}\right)^{-1}\right)^3 \] Alternatively, more straightforwardly: \[ \left(\frac{1}{3}\right)^{-3} = \left(\frac{1}{3}\right)^{-1 \times 3} = \left(\frac{1}{3}\right)^{-3} \] And applying the rule \(a^{-n} = \frac{1}{a^n}\): \[ \left(\frac{1}{3}\right)^{-3} = \left(\frac{1}{\left(\frac{1}{3}\right)^3}\right) = \frac{1}{\frac{1}{27}} = 27 \] **Answer: \(\boxed{27}\)**