(1/3)^-3

To evaluate \(\left(\frac{1}{3}\right)^{-3}\):

Using the property of exponents, \(a^{-n} = \frac{1}{a^n}\),

\[ \left(\frac{1}{3}\right)^{-3} = \left(\frac{1}{3}\right)^{-1 \times 3} = \left(\left(\frac{1}{3}\right)^{-1}\right)^3 \]

Alternatively, more straightforwardly:

\[ \left(\frac{1}{3}\right)^{-3} = \left(\frac{1}{3}\right)^{-1 \times 3} = \left(\frac{1}{3}\right)^{-3} \]

And applying the rule \(a^{-n} = \frac{1}{a^n}\):

\[ \left(\frac{1}{3}\right)^{-3} = \left(\frac{1}{\left(\frac{1}{3}\right)^3}\right) = \frac{1}{\frac{1}{27}} = 27 \]

Answer: \(\boxed{27}\)