5737473747374737373737374747^474747374737374747474773

Nice big exponent. If you’re just asking for a quick property, here’s one common check:

• Let A = 5737473747374737373737374747 (the base) and B = 474747374737374747474773 (the exponent).
• To get the last digit of A^B:
  • A ends with 7, so A ≡ 7 (mod 10).
  • The last-digit cycle of powers of 7 is 7, 9, 3, 1 (period 4).
  • B ends with 73, so B ≡ 1 (mod 4).
  • Therefore A^B ≡ 7^1 ≡ 7 (mod 10).

So the last digit of the result is 7.

If you want more than the last digit (e.g., last k digits, or the result modulo some m, or the total number of digits), tell me what you need and the modulus/digit count, and I’ll show the method.