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Вопрос от Анонимного юзера 08 января 2025 19:01

X2+x-12 ----------- x2+8x+16

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08 января 2025 19:01

To simplify the expression (\frac{x^2 + x - 12}{x^2 + 8x + 16}), we need to factor both the numerator and the denominator, if possible.

Step 1: Factor the numerator (x^2 + x - 12)

To factor (x^2 + x - 12), we need to find two numbers that multiply to (-12) and add to (1). These numbers are (4) and (-3).

So, we can factor the numerator:

[ x^2 + x - 12 = (x + 4)(x - 3) ]

Step 2: Factor the denominator (x^2 + 8x + 16)

To factor (x^2 + 8x + 16), we look for two numbers that multiply to (16) and add to (8). These numbers are (4) and (4).

So, we can factor the denominator:

[ x^2 + 8x + 16 = (x + 4)(x + 4) = (x + 4)^2 ]

Step 3: Rewrite the expression with the factors

Now we can rewrite the original expression with the factored forms:

[ \frac{x^2 + x - 12}{x^2 + 8x + 16} = \frac{(x + 4)(x - 3)}{(x + 4)(x + 4)} ]

Step 4: Simplify the expression

We can cancel out the ((x + 4)) term from the numerator and the denominator (assuming (x \neq -4) since it would lead to division by zero):

[ = \frac{x - 3}{x + 4} \quad (x \neq -4) ]

Thus, the simplified form of the expression is

[ \frac{x - 3}{x + 4} \quad (x \neq -4) ]

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x2+x-12 ----------- x2+8x+16
To simplify the expression \(\frac{x^2 + x - 12}{x^2 + 8x + 16}\), we need to factor both the numerator and the denominator, if possible. **Step 1: Factor the numerator \(x^2 + x - 12\)** To factor \(x^2 + x - 12\), we need to find two numbers that multiply to \(-12\) and add to \(1\). These numbers are \(4\) and \(-3\). So, we can factor the numerator: \[ x^2 + x - 12 = (x + 4)(x - 3) \] **Step 2: Factor the denominator \(x^2 + 8x + 16\)** To factor \(x^2 + 8x + 16\), we look for two numbers that multiply to \(16\) and add to \(8\). These numbers are \(4\) and \(4\). So, we can factor the denominator: \[ x^2 + 8x + 16 = (x + 4)(x + 4) = (x + 4)^2 \] **Step 3: Rewrite the expression with the factors** Now we can rewrite the original expression with the factored forms: \[ \frac{x^2 + x - 12}{x^2 + 8x + 16} = \frac{(x + 4)(x - 3)}{(x + 4)(x + 4)} \] **Step 4: Simplify the expression** We can cancel out the \((x + 4)\) term from the numerator and the denominator (assuming \(x \neq -4\) since it would lead to division by zero): \[ = \frac{x - 3}{x + 4} \quad (x \neq -4) \] Thus, the simplified form of the expression is \[ \frac{x - 3}{x + 4} \quad (x \neq -4) \]