11*(7/6+2/3)

To solve the expression \( 11 \times \left( \frac{7}{6} + \frac{2}{3} \right) \), we first need to simplify the term inside the parentheses.

1. Find a common denominator for the fractions \( \frac{7}{6} \) and \( \frac{2}{3} \). The least common denominator (LCD) of 6 and 3 is 6.

2. Rewrite \( \frac{2}{3} \) with a denominator of 6: \[ \frac{2}{3} = \frac{2 \times 2}{3 \times 2} = \frac{4}{6} \]

3. Now, we can add the two fractions: \[ \frac{7}{6} + \frac{4}{6} = \frac{7 + 4}{6} = \frac{11}{6} \]

4. Now multiply this result by 11: \[ 11 \times \frac{11}{6} = \frac{11 \times 11}{6} = \frac{121}{6} \]

Thus, the final answer is: \[ \frac{121}{6} \]

If you wish to convert this to a mixed number, you can divide 121 by 6: \[ 121 \div 6 = 20 \quad \text{remainder} \quad 1 \]

So, it can also be expressed as: \[ 20 \frac{1}{6} \]

Final answers: \[ \frac{121}{6} \quad \text{or} \quad 20 \frac{1}{6} \]