Y = (x^4 - 7) / (4^4).
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23 января 2025 06:08
To analyze the function ( y = \frac{x^4 - 7}{4^4} ), we can simplify it first:
Since ( 4^4 = 256 ), the equation can be rewritten as:
[ y = \frac{x^4 - 7}{256} ]
This is a polynomial function where the numerator ( x^4 - 7 ) is a quartic polynomial, and the denominator is a constant.
Key Characteristics
Domain: The domain of ( y ) is all real numbers ( x ) since there are no restrictions (the polynomial can take any real value).
Intercepts:
y-intercept: Set ( x = 0 ): [ y = \frac{0^4 - 7}{256} = \frac{-7}{256} ] So the y-intercept is at ( (0, -\frac{7}{256}) ).
x-intercepts: Set ( y = 0 ): [ \frac{x^4 - 7}{256} = 0 \implies x^4 - 7 = 0 \implies x^4 = 7 \implies x = \pm \sqrt[4]{7} ] Thus, the x-intercepts are at ( (\sqrt[4]{7}, 0) ) and ( (-\sqrt[4]{7}, 0) ).
Behavior: As ( x ) approaches ( \pm \infty ), ( x^4 ) dominates, thus ( y \to \infty ). As ( x ) approaches ( 0 ), ( y ) approaches ( -\frac{7}{256} ).
Symmetry: The function is even since ( y(x) = y(-x) ). This means the graph is symmetric with respect to the y-axis.
Critical Points and Extrema: To find the critical points, we can take the derivative and set it to zero:
- Using the quotient rule: [ y' = \frac{(4x^3)(256) - (1)(x^4 - 7)(0)}{256^2} = \frac{1024 x^3}{256} = \frac{4x^3}{1} ] Setting ( y' = 0 ): [ 4x^3 = 0 \implies x = 0 ] To determine if this is a maximum or minimum, we can examine the second derivative or use the first derivative test.
Second Derivative: ( y'' = 12x^2 ). Since the second derivative is non-negative for all ( x ), ( x = 0 ) is a local minimum.
Summary
- Function: ( y = \frac{x^4 - 7}{256} )
- Domain: All real numbers (( \mathbb{R} ))
- Intercepts: y-intercept at ( (0, -\frac{7}{256}) ), x-intercepts at ( (\sqrt[4]{7}, 0) ) and ( (-\sqrt[4]{7}, 0) )
- Local Minimum: at ( (0, -\frac{7}{256}) )
You can further analyze the graph based on this information or explore any additional specific aspects you're interested in!
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