1.5x-5/3x^3;[0;2]
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03 февраля 2025 02:08
To analyze the function ( f(x) = \frac{1.5x - 5}{3x^3} ) on the interval ([0, 2]), we first rewrite the function in a more manageable form:
[ f(x) = \frac{1.5x - 5}{3x^3} = \frac{1.5}{3} \cdot \frac{x - \frac{10}{3}}{x^3} = \frac{0.5(x - \frac{10}{3})}{x^3} ]
Next, we need to examine the interval ([0, 2]) and identify any critical points, discontinuities, or end behavior.
Step 1: Domain Considerations
The function is defined for ( x \neq 0 ) because of the ( x^3 ) denominator. Therefore, the domain on the interval ([0, 2]) is any point in ((0, 2]).
Step 2: Finding Critical Points
To find the critical points, we first need to take the derivative of ( f(x) ) and set it to zero:
Using the quotient rule:
[ f'(x) = \frac{(3x^3)(1.5) - (1.5x - 5)(9x^2)}{(3x^3)^2} ]
Simplifying the numerator:
- ( 3x^3 \cdot 1.5 = 4.5x^3 )
- Distribute ( (1.5x - 5)(9x^2) ):
[ (1.5x)(9x^2) - (5)(9x^2) = 13.5x^3 - 45x^2 ]
So the derivative becomes:
[ f'(x) = \frac{4.5x^3 - (13.5x^3 - 45x^2)}{(3x^3)^2} = \frac{4.5x^3 - 13.5x^3 + 45x^2}{9x^6} ]
[ = \frac{-9x^3 + 45x^2}{9x^6} = \frac{45x^2 - 9x^3}{9x^6} ]
Setting the numerator equal to zero:
[ 45x^2 - 9x^3 = 0 \ 9x^2(5 - x) = 0 ]
This gives us critical points ( x = 0 ) (not in the domain) and ( x = 5 ) (not in the interval).
Step 3: Evaluate Endpoints in the Interval
Since ( x = 0 ) is not in the domain and there are no critical points in the interval ((0, 2]), we evaluate the function at the endpoint ( x = 2 ).
[ f(2) = \frac{1.5(2) - 5}{3(2)^3} = \frac{3 - 5}{3 \cdot 8} = \frac{-2}{24} = -\frac{1}{12} ]
Step 4: Conclusion
The function ( f(x) ) is decreasing towards ( x = 2 ) and goes to ( -\infty ) as ( x ) approaches ( 0 ) from the right. The only value we can confirm in the specified interval is at the endpoint:
- ( f(2) = -\frac{1}{12} )
Thus, the only output of interest in the interval [0, 2] is:
- The function approaches ( -\infty ) as ( x ) approaches ( 0^+ ),
- ( f(2) = -\frac{1}{12} ).
If you have further questions or need additional analysis or specific points of interest, feel free to ask!
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