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Вопрос от Анонимного юзера 24 февраля 2025 21:58

1) x - 2 1/5 = 5 2/5 2) (x - 3 13/24) + 210/- 24 =7 x c1 3 (x + 2 4/11) - 4 * z/11 = 1 * (5 * c')/71 (4) 3 5/7 + x = 9 1/7

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24 февраля 2025 21:58

Let's solve each equation one by one.

Problem 1:

Equation: [ x - 2 \frac{1}{5} = 5 \frac{2}{5} ]

Solution:

  1. Convert mixed numbers to improper fractions:

    • ( 2 \frac{1}{5} = \frac{11}{5} )
    • ( 5 \frac{2}{5} = \frac{27}{5} )
  2. Rewrite the equation: [ x - \frac{11}{5} = \frac{27}{5} ]

  3. Add ( \frac{11}{5} ) to both sides: [ x = \frac{27}{5} + \frac{11}{5} ] [ x = \frac{27 + 11}{5} ] [ x = \frac{38}{5} ] [ x = 7 \frac{3}{5} ]

Problem 2:

Equation: [ (x - 3 \frac{13}{24}) + \frac{210}{-24} = 7 \times c_1 ]

Solution:

  1. Convert the mixed number to an improper fraction:

    • ( 3 \frac{13}{24} = \frac{72 + 13}{24} = \frac{85}{24} )
  2. Rewrite the equation: [ (x - \frac{85}{24}) - \frac{210}{24} = 7 \times c_1 ]

  3. Combine the constants on the left side: [ x - \frac{85 + 210}{24} = 7 \times c_1 ] [ x - \frac{295}{24} = 7c_1 ]

  4. Add ( \frac{295}{24} ) to both sides: [ x = 7c_1 + \frac{295}{24} ]

Problem 3:

Equation: [ (x + 2 \frac{4}{11}) - \frac{4z}{11} = 1 \cdot \frac{5c'}{71} ]

Solution:

  1. Convert the mixed number to an improper fraction:

    • ( 2 \frac{4}{11} = \frac{22 + 4}{11} = \frac{26}{11} )
  2. Rewrite the equation: [ (x + \frac{26}{11}) - \frac{4z}{11} = \frac{5c'}{71} ]

  3. Combine the constants on the left side: [ x + \frac{26}{11} - \frac{4z}{11} = \frac{5c'}{71} ] [ x = \frac{5c'}{71} - \frac{26}{11} + \frac{4z}{11} ]

Problem 4:

Equation: [ 3 \frac{5}{7} + x = 9 \frac{1}{7} ]

Solution:

  1. Convert the mixed numbers to improper fractions:

    • ( 3 \frac{5}{7} = \frac{26}{7} )
    • ( 9 \frac{1}{7} = \frac{64}{7} )
  2. Rewrite the equation: [ \frac{26}{7} + x = \frac{64}{7} ]

  3. Subtract ( \frac{26}{7} ) from both sides: [ x = \frac{64}{7} - \frac{26}{7} ] [ x = \frac{64 - 26}{7} ] [ x = \frac{38}{7} ] [ x = 5 \frac{3}{7} ]

Summary of Results:

  1. ( x = 7 \frac{3}{5} )
  2. ( x = 7c_1 + \frac{295}{24} )
  3. ( x = \frac{5c'}{71} - \frac{26}{11} + \frac{4z}{11} )
  4. ( x = 5 \frac{3}{7} )

If you need any further clarification or additional problems to solve, feel free to ask!

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1) x - 2 1/5 = 5 2/5 2) (x - 3 13/24) + 210/- 24 =7 x c1 3 (x + 2 4/11) - 4 * z/11 = 1 * (5 * c')/71 (4) 3 5/7 + x = 9 1/7
Let's solve each equation one by one. ### Problem 1: **Equation**: \[ x - 2 \frac{1}{5} = 5 \frac{2}{5} \] **Solution**: 1. Convert mixed numbers to improper fractions: - \( 2 \frac{1}{5} = \frac{11}{5} \) - \( 5 \frac{2}{5} = \frac{27}{5} \) 2. Rewrite the equation: \[ x - \frac{11}{5} = \frac{27}{5} \] 3. Add \( \frac{11}{5} \) to both sides: \[ x = \frac{27}{5} + \frac{11}{5} \] \[ x = \frac{27 + 11}{5} \] \[ x = \frac{38}{5} \] \[ x = 7 \frac{3}{5} \] ### Problem 2: **Equation**: \[ (x - 3 \frac{13}{24}) + \frac{210}{-24} = 7 \times c_1 \] **Solution**: 1. Convert the mixed number to an improper fraction: - \( 3 \frac{13}{24} = \frac{72 + 13}{24} = \frac{85}{24} \) 2. Rewrite the equation: \[ (x - \frac{85}{24}) - \frac{210}{24} = 7 \times c_1 \] 3. Combine the constants on the left side: \[ x - \frac{85 + 210}{24} = 7 \times c_1 \] \[ x - \frac{295}{24} = 7c_1 \] 4. Add \( \frac{295}{24} \) to both sides: \[ x = 7c_1 + \frac{295}{24} \] ### Problem 3: **Equation**: \[ (x + 2 \frac{4}{11}) - \frac{4z}{11} = 1 \cdot \frac{5c'}{71} \] **Solution**: 1. Convert the mixed number to an improper fraction: - \( 2 \frac{4}{11} = \frac{22 + 4}{11} = \frac{26}{11} \) 2. Rewrite the equation: \[ (x + \frac{26}{11}) - \frac{4z}{11} = \frac{5c'}{71} \] 3. Combine the constants on the left side: \[ x + \frac{26}{11} - \frac{4z}{11} = \frac{5c'}{71} \] \[ x = \frac{5c'}{71} - \frac{26}{11} + \frac{4z}{11} \] ### Problem 4: **Equation**: \[ 3 \frac{5}{7} + x = 9 \frac{1}{7} \] **Solution**: 1. Convert the mixed numbers to improper fractions: - \( 3 \frac{5}{7} = \frac{26}{7} \) - \( 9 \frac{1}{7} = \frac{64}{7} \) 2. Rewrite the equation: \[ \frac{26}{7} + x = \frac{64}{7} \] 3. Subtract \( \frac{26}{7} \) from both sides: \[ x = \frac{64}{7} - \frac{26}{7} \] \[ x = \frac{64 - 26}{7} \] \[ x = \frac{38}{7} \] \[ x = 5 \frac{3}{7} \] ### Summary of Results: 1. \( x = 7 \frac{3}{5} \) 2. \( x = 7c_1 + \frac{295}{24} \) 3. \( x = \frac{5c'}{71} - \frac{26}{11} + \frac{4z}{11} \) 4. \( x = 5 \frac{3}{7} \) If you need any further clarification or additional problems to solve, feel free to ask!