1) x - 2 1/5 = 5 2/5 2) (x - 3 13/24) + 210/- 24 =7 x c1 3 (x + 2 4/11) - 4 * z/11 = 1 * (5 * c')/71 (4) 3 5/7 + x = 9 1/7
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24 февраля 2025 21:58
Let's solve each equation one by one.
Problem 1:
Equation: [ x - 2 \frac{1}{5} = 5 \frac{2}{5} ]
Solution:
Convert mixed numbers to improper fractions:
- ( 2 \frac{1}{5} = \frac{11}{5} )
- ( 5 \frac{2}{5} = \frac{27}{5} )
Rewrite the equation: [ x - \frac{11}{5} = \frac{27}{5} ]
Add ( \frac{11}{5} ) to both sides: [ x = \frac{27}{5} + \frac{11}{5} ] [ x = \frac{27 + 11}{5} ] [ x = \frac{38}{5} ] [ x = 7 \frac{3}{5} ]
Problem 2:
Equation: [ (x - 3 \frac{13}{24}) + \frac{210}{-24} = 7 \times c_1 ]
Solution:
Convert the mixed number to an improper fraction:
- ( 3 \frac{13}{24} = \frac{72 + 13}{24} = \frac{85}{24} )
Rewrite the equation: [ (x - \frac{85}{24}) - \frac{210}{24} = 7 \times c_1 ]
Combine the constants on the left side: [ x - \frac{85 + 210}{24} = 7 \times c_1 ] [ x - \frac{295}{24} = 7c_1 ]
Add ( \frac{295}{24} ) to both sides: [ x = 7c_1 + \frac{295}{24} ]
Problem 3:
Equation: [ (x + 2 \frac{4}{11}) - \frac{4z}{11} = 1 \cdot \frac{5c'}{71} ]
Solution:
Convert the mixed number to an improper fraction:
- ( 2 \frac{4}{11} = \frac{22 + 4}{11} = \frac{26}{11} )
Rewrite the equation: [ (x + \frac{26}{11}) - \frac{4z}{11} = \frac{5c'}{71} ]
Combine the constants on the left side: [ x + \frac{26}{11} - \frac{4z}{11} = \frac{5c'}{71} ] [ x = \frac{5c'}{71} - \frac{26}{11} + \frac{4z}{11} ]
Problem 4:
Equation: [ 3 \frac{5}{7} + x = 9 \frac{1}{7} ]
Solution:
Convert the mixed numbers to improper fractions:
- ( 3 \frac{5}{7} = \frac{26}{7} )
- ( 9 \frac{1}{7} = \frac{64}{7} )
Rewrite the equation: [ \frac{26}{7} + x = \frac{64}{7} ]
Subtract ( \frac{26}{7} ) from both sides: [ x = \frac{64}{7} - \frac{26}{7} ] [ x = \frac{64 - 26}{7} ] [ x = \frac{38}{7} ] [ x = 5 \frac{3}{7} ]
Summary of Results:
- ( x = 7 \frac{3}{5} )
- ( x = 7c_1 + \frac{295}{24} )
- ( x = \frac{5c'}{71} - \frac{26}{11} + \frac{4z}{11} )
- ( x = 5 \frac{3}{7} )
If you need any further clarification or additional problems to solve, feel free to ask!
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