Let's solve each equation one by one.
Problem 1:
Equation: \[ x - 2 \frac{1}{5} = 5 \frac{2}{5} \]
Solution:
Convert mixed numbers to improper fractions:
- \( 2 \frac{1}{5} = \frac{11}{5} \)
- \( 5 \frac{2}{5} = \frac{27}{5} \)
Rewrite the equation: \[ x - \frac{11}{5} = \frac{27}{5} \]
Add \( \frac{11}{5} \) to both sides: \[ x = \frac{27}{5} + \frac{11}{5} \] \[ x = \frac{27 + 11}{5} \] \[ x = \frac{38}{5} \] \[ x = 7 \frac{3}{5} \]
Problem 2:
Equation: \[ (x - 3 \frac{13}{24}) + \frac{210}{-24} = 7 \times c_1 \]
Solution:
Convert the mixed number to an improper fraction:
- \( 3 \frac{13}{24} = \frac{72 + 13}{24} = \frac{85}{24} \)
Rewrite the equation: \[ (x - \frac{85}{24}) - \frac{210}{24} = 7 \times c_1 \]
Combine the constants on the left side: \[ x - \frac{85 + 210}{24} = 7 \times c_1 \] \[ x - \frac{295}{24} = 7c_1 \]
Add \( \frac{295}{24} \) to both sides: \[ x = 7c_1 + \frac{295}{24} \]
Problem 3:
Equation: \[ (x + 2 \frac{4}{11}) - \frac{4z}{11} = 1 \cdot \frac{5c'}{71} \]
Solution:
Convert the mixed number to an improper fraction:
- \( 2 \frac{4}{11} = \frac{22 + 4}{11} = \frac{26}{11} \)
Rewrite the equation: \[ (x + \frac{26}{11}) - \frac{4z}{11} = \frac{5c'}{71} \]
Combine the constants on the left side: \[ x + \frac{26}{11} - \frac{4z}{11} = \frac{5c'}{71} \] \[ x = \frac{5c'}{71} - \frac{26}{11} + \frac{4z}{11} \]
Problem 4:
Equation: \[ 3 \frac{5}{7} + x = 9 \frac{1}{7} \]
Solution:
Convert the mixed numbers to improper fractions:
- \( 3 \frac{5}{7} = \frac{26}{7} \)
- \( 9 \frac{1}{7} = \frac{64}{7} \)
Rewrite the equation: \[ \frac{26}{7} + x = \frac{64}{7} \]
Subtract \( \frac{26}{7} \) from both sides: \[ x = \frac{64}{7} - \frac{26}{7} \] \[ x = \frac{64 - 26}{7} \] \[ x = \frac{38}{7} \] \[ x = 5 \frac{3}{7} \]
Summary of Results:
- \( x = 7 \frac{3}{5} \)
- \( x = 7c_1 + \frac{295}{24} \)
- \( x = \frac{5c'}{71} - \frac{26}{11} + \frac{4z}{11} \)
- \( x = 5 \frac{3}{7} \)
If you need any further clarification or additional problems to solve, feel free to ask!