t1=400c t2=210c Q=14500дж c=380дж/кг*с m-?

To find the mass \( m \) of the substance given the temperatures \( t_1 \) and \( t_2 \), the heat transfer \( Q \), and the specific heat capacity \( c \), you can use the formula for heat transfer:

\[ Q = m \cdot c \cdot \Delta t \]

where:

• \( Q \) is the heat transfer (in joules),
• \( m \) is the mass (in kilograms),
• \( c \) is the specific heat capacity (in joules per kilogram per degree Celsius),
• \( \Delta t \) is the change in temperature (in degrees Celsius).

First, calculate the change in temperature \( \Delta t \):

\[ \Delta t = t_1 - t_2 = 400^\circ C - 210^\circ C = 190^\circ C \]

Now substitute the known values into the formula:

\[ 14500 \, \text{J} = m \cdot 380 \, \text{J/(kg}\cdot^\circ C) \cdot 190 \, ^\circ C \]

Now simplify the equation:

\[ 14500 = m \cdot 380 \cdot 190 \]

Calculate \( 380 \cdot 190 \):

\[ 380 \cdot 190 = 72200 \]

So the equation is now:

\[ 14500 = m \cdot 72200 \]

Now, solve for \( m \):

\[ m = \frac{14500}{72200} \approx 0.2005 \, \text{kg} \]

Thus, the mass \( m \) is approximately \( 0.2005 \, \text{kg} \) or about \( 200.5 \, \text{g} \).