To simplify the expression given, we can first rewrite each term in terms of positive exponents:
\(81^{-0.75} = \frac{1}{81^{0.75}} = \frac{1}{(3^4)^{0.75}} = \frac{1}{3^{3}} = \frac{1}{27} \)
\( \frac{1}{125^{-1/3}} = 125^{1/3} = \sqrt[3]{125} = 5\)
\( \frac{1}{32^{-3/5}} = 32^{3/5} = \sqrt[5]{32^3} = \sqrt[5]{32^3} = \sqrt[5]{32768} = 8\)
Now we can substitute these values back into the expression:
\( \frac{1}{27} + 5 - 8 = \frac{1}{27} - 3 \)
At this point, to add fractions with unlike denominators, we need to find a common denominator. The common denominator for \(27\) and \(1\) is \(27\), so the expression becomes:
\( \frac{1}{27} - \frac{81}{27} = \frac{1 - 81}{27} = \frac{-80}{27}\)
Therefore, the simplified form of the expression is \( \frac{-80}{27} \).