To solve the quadratic equation \(x^2 + 3x + 2 = 0\), we can factor the equation.
Factoring: We look for two numbers that multiply to \(2\) (the constant term) and add up to \(3\) (the coefficient of \(x\)).
The numbers \(1\) and \(2\) work because:
- \(1 \times 2 = 2\)
- \(1 + 2 = 3\)
So we can factor the quadratic equation as: \[ (x + 1)(x + 2) = 0 \]
Setting each factor to zero: Now, we set each factor equal to zero: \[ x + 1 = 0 \quad \text{or} \quad x + 2 = 0 \]
Solving these equations gives: \[ x = -1 \quad \text{or} \quad x = -2 \]
Solutions: The solutions to the equation \(x^2 + 3x + 2 = 0\) are: \[ x = -1 \quad \text{and} \quad x = -2 \]
Thus, the final answer is \(x = -1\) and \(x = -2\).