Y=12 11x-3y=8

To solve the system of equations given: 1. \( y = 12 \) 2. \( 11x - 3y = 8 \) We can substitute the value of \( y \) from the first equation into the second equation. Substituting \( y = 12 \) into the second equation: \[ 11x - 3(12) = 8 \] This simplifies to: \[ 11x - 36 = 8 \] Next, we add 36 to both sides: \[ 11x = 8 + 36 \] \[ 11x = 44 \] Now, divide both sides by 11: \[ x = \frac{44}{11} = 4 \] So, the solution to the system of equations is: \[ x = 4, \quad y = 12 \] The final ordered pair solution is \( (4, 12) \).