y=12 11x-3y=8

To solve the system of equations given:

1. \( y = 12 \)
2. \( 11x - 3y = 8 \)

We can substitute the value of \( y \) from the first equation into the second equation.

Substituting \( y = 12 \) into the second equation:

\[ 11x - 3(12) = 8 \]

This simplifies to:

\[ 11x - 36 = 8 \]

Next, we add 36 to both sides:

\[ 11x = 8 + 36 \]

\[ 11x = 44 \]

Now, divide both sides by 11:

\[ x = \frac{44}{11} = 4 \]

So, the solution to the system of equations is:

\[ x = 4, \quad y = 12 \]

The final ordered pair solution is \( (4, 12) \).