log2 (15*6)

To simplify \(\log_2(15 \times 6)\), you can use the property of logarithms that states:

\[ \log_b(m \times n) = \log_b(m) + \log_b(n) \]

So, we can rewrite the expression as:

\[ \log_2(15 \times 6) = \log_2(15) + \log_2(6) \]

Now, if you want to calculate the value numerically, you can use the change of base formula:

\[ \log_2(x) = \frac{\log_{10}(x)}{\log_{10}(2)} \]

Calculating:

1. \(\log_{10}(15) \approx 1.1761\)
2. \(\log_{10}(6) \approx 0.7781\)
3. \(\log_{10}(2) \approx 0.3010\)

So,

\[ \log_2(15) \approx \frac{1.1761}{0.3010} \approx 3.905 \] \[ \log_2(6) \approx \frac{0.7781}{0.3010} \approx 2.585 \]

Now, adding these values together:

\[ \log_2(15 \times 6) \approx 3.905 + 2.585 \approx 6.490 \]

Thus, \(\log_2(90) \approx 6.490\).