To solve the expression \((\frac{1}{30} + \frac{3}{20}) \cdot 6\), we first need to find a common denominator for the fractions \(\frac{1}{30}\) and \(\frac{3}{20}\).
The least common multiple (LCM) of 30 and 20 is 60. Now, we convert each fraction:
\[ \frac{1}{30} = \frac{1 \times 2}{30 \times 2} = \frac{2}{60} \]
\[ \frac{3}{20} = \frac{3 \times 3}{20 \times 3} = \frac{9}{60} \]
Now we can add the two fractions:
\[ \frac{2}{60} + \frac{9}{60} = \frac{2 + 9}{60} = \frac{11}{60} \]
Next, we multiply this sum by 6:
\[ \frac{11}{60} \cdot 6 = \frac{11 \cdot 6}{60} = \frac{66}{60} \]
Finally, we simplify \(\frac{66}{60}\):
Dividing both the numerator and denominator by 6, we get:
\[ \frac{66 \div 6}{60 \div 6} = \frac{11}{10} \]
Thus, the final result is:
\[ \frac{11}{10} \text{ or } 1.1 \]