27^2/3+1/16^-0,75-25^0,5

To solve this expression, let's break it down step by step: 1. \(27^{2/3}\): This means the cube root of 27 squared. First, calculate 27 squared: \(27^2 = 729\). Then, calculate the cube root of 729: \( \sqrt[3]{729} = 9 \). So, \(27^{2/3} = 9\). 2. \(1/16^{-0.75}\): This means 1 divided by 16 to the power of -0.75. First, calculate \(16^{-0.75}\): \(16^{-0.75} = \frac{1}{16^{0.75}} = \frac{1}{\sqrt[4]{16^3}} = \frac{1}{\sqrt[4]{4096}} = \frac{1}{16}\). Therefore, \(1/16^{-0.75} = 1/(1/16) = 16\). 3. \(25^{0.5}\): This means the square root of 25. Calculating the square root of 25 gives: \(\sqrt{25}=5\). Now, put it all together: \(27^{2/3} + 1/16^{-0.75} - 25^{0.5} = 9 + 16 - 5 = 20\). Therefore, the final result is 20.